According to the model sq rt distance = 3.30 + 0.235(speed), approximately how much stopping distance is needed for a car going 65 mph?

According to the model sq rt distance = 3.30 + 0.235(speed), approximately how much stopping distance is needed for a car going 65 mph?

• A. 345.0 feet
• B. 200.0 feet
• C. 275.0 feet
• D. 400.0 feet

Answer: (A)

To determine the stopping distance needed for a car going 65 mph using the given model, we first need to substitute the speed value into the equation. The model provided is: \[ \sqrt{\text{distance}} = 3.30 + 0.235(\text{speed}) \] Substituting the speed of 65 mph into the equation gives: \[ \sqrt{\text{distance}} = 3.30 + 0.235(65) \] Calculating \(0.235 \times 65\): \[ 0.235 \times 65 = 15.275 \] Now, adding this to 3.30: \[ \sqrt{\text{distance}} = 3.30 + 15.275 = 18.575 \] Next, to find the stopping distance, we need to square the result: \[ \text{distance} = (18.575)^2 \] Calculating this gives: \[ \text{distance} \approx 345.0 \text{ feet} \] This matches the answer provided, confirming that for a car traveling at 65 mph, approximately 345.0 feet of stopping distance is required

To determine the stopping distance needed for a car going 65 mph using the given model, we first need to substitute the speed value into the equation. The model provided is:

[

\sqrt{\text{distance}} = 3.30 + 0.235(\text{speed})

]

Substituting the speed of 65 mph into the equation gives:

[

\sqrt{\text{distance}} = 3.30 + 0.235(65)

]

Calculating (0.235 \times 65):

[

0.235 \times 65 = 15.275

]

Now, adding this to 3.30:

[

\sqrt{\text{distance}} = 3.30 + 15.275 = 18.575

]

Next, to find the stopping distance, we need to square the result:

[

\text{distance} = (18.575)^2

]

Calculating this gives:

[

\text{distance} \approx 345.0 \text{ feet}

]

This matches the answer provided, confirming that for a car traveling at 65 mph, approximately 345.0 feet of stopping distance is required